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Thanks for the question, Saket.
Asked: March 05, 2018 - 6:10 am UTC
Last updated: March 05, 2018 - 10:53 am UTC
Version: 11g
Viewed 1000+ times
update hr.employees set salary = 7000 where department_id = 100 and salary <= 7800; select salary, rank() over (order by salary) rk, dense_rank() over (order by salary) dr from hr.employees where department_id = 100; SALARY RK DR 7000 1 1 7000 1 1 7000 1 1 8200 4 2 9000 5 3 12008 6 4
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