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Thanks for the question, Demongo.
Asked: September 23, 2015 - 10:18 am UTC
Last updated: July 14, 2017 - 3:09 pm UTC
Version: 11g
Viewed 1000+ times
create view requests_all as select r.*, n.*, o.* from requests r left join requests_new n on r.id = n.id left join requests_old o on r.id = o.id;
David Aldridge, September 24, 2015 - 9:28 pm UTC
Duke Ganote, October 01, 2015 - 12:28 pm UTC
Debabrata Kabiraj, July 14, 2017 - 1:30 pm UTC
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