Thanks for the question.
Asked: February 25, 2021 - 9:18 am UTC
Last updated: February 26, 2021 - 11:46 am UTC
Version: PLSQL developer
Viewed 1000+ times
([0-9][0-9])([0-9][0-9])
\1:\2
with rws as ( select '1234abc5678' str from dual ) select regexp_replace ( str, '([0-9][0-9])([0-9][0-9])', '\1:\2' ) s from rws; S 12:34abc56:78
A reader, February 26, 2021 - 12:51 pm UTC
The Oracle documentation contains a complete SQL reference.