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Question and Answer

Tom Kyte

Thanks for the question, Yuri.

Asked: November 26, 2014 - 9:06 am UTC

Last updated: November 26, 2014 - 4:53 pm UTC

Version: 11.2.0

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You Asked

Hi, Tom.
I need to create a bulk of serial numbers in one of my tables and for that I want to create a stored procedure. I want to pass first SN and last SN and the procedure to return all the SN in between these two.
How can I do that without using loops?
For example I pass to the procedure '300RASEL0000000671000001' and '300RASEL0000000671000010' and should get the following:
'300RASEL0000000671000001'
'300RASEL0000000671000002'
'300RASEL0000000671000003'
...
'300RASEL0000000671000010'

Thank you in advance

and Tom said...

You don't need a stored procedure :)

A simple select will do it


ops$tkyte%ORA11GR2> variable s varchar2(30)
ops$tkyte%ORA11GR2> variable e varchar2(30)
ops$tkyte%ORA11GR2> 
ops$tkyte%ORA11GR2> exec :s := '300RASEL0000000671000001'

PL/SQL procedure successfully completed.

ops$tkyte%ORA11GR2> exec :e := '300RASEL0000000671000010'

PL/SQL procedure successfully completed.

ops$tkyte%ORA11GR2> 
ops$tkyte%ORA11GR2> select substr( :s, 1, 18 ) || to_char( to_number( substr( :s, 19 ) )+level-1, 'fm000000' )
  2    from dual
  3  connect by level <= to_number( substr( :e, 19 ) )-to_number( substr( :s, 19 ) )+1
  4  /

SUBSTR(:S,1,18)||TO_CHAR(
-------------------------
300RASEL0000000671000001
300RASEL0000000671000002
300RASEL0000000671000003
300RASEL0000000671000004
300RASEL0000000671000005
300RASEL0000000671000006
300RASEL0000000671000007
300RASEL0000000671000008
300RASEL0000000671000009
300RASEL0000000671000010

10 rows selected.


or using the "newer" recursive with clause:

ops$tkyte%ORA11GR2> with data (sn)
  2  as
  3  ( select to_number( substr( :s, 19 ) ) sn from dual
  4    union all
  5    select sn+1 from data where sn <= to_number( substr( :e, 19 ) )-to_number( substr( :s, 19 ) )
  6  )
  7  select substr( :s, 1, 18 ) || to_char( sn, 'fm000000' )
  8    from data
  9  /

SUBSTR(:S,1,18)||TO_CHAR(
-------------------------
300RASEL0000000671000001
300RASEL0000000671000002
300RASEL0000000671000003
300RASEL0000000671000004
300RASEL0000000671000005
300RASEL0000000671000006
300RASEL0000000671000007
300RASEL0000000671000008
300RASEL0000000671000009
300RASEL0000000671000010

10 rows selected.

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Comments

Great

Yuri Mayorov, November 27, 2014 - 6:39 am UTC

Tom,
thank you so much! That's a great solution
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