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Thanks for the question, Rajesh.
Asked: August 29, 2016 - 10:03 pm UTC
Last updated: August 30, 2016 - 3:06 am UTC
Version: 11G
Viewed 1000+ times
SQL> select email, replace(lower(email),'b@gmail.com','BB@gmail.com') x from details; EMAIL X -------------------------------------------------- ------------------------------------------- AA@yahoo.com aa@yahoo.com b@gmail.com BB@gmail.com AA@yahoo.com,b@gmail.com,c@hotmail.com aa@yahoo.com,BB@gmail.com,c@hotmail.com
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